18x^2-48x=-32

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Solution for 18x^2-48x=-32 equation:



18x^2-48x=-32
We move all terms to the left:
18x^2-48x-(-32)=0
We add all the numbers together, and all the variables
18x^2-48x+32=0
a = 18; b = -48; c = +32;
Δ = b2-4ac
Δ = -482-4·18·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{48}{36}=1+1/3$

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